Work = force x distance.
force = mass x acceleration
work = mass x acceleration x diastance
use acceleration of gravity in this problem
W (J) = m (kg) x a (m/s/s) x d (m)
W = 78 x 9.8 x 6
W = 4586.4
A) Net force in component form: 
B) Magnitude of the net force: 316.2, direction: 
Explanation:
A)
The three forces given in this problem are:



The three forces are given in component form, where the components with unit vector i is the component along the x-direction, while the components with unit vector j is the component along the y-direction.
In order to find the net force in component form, we just need to add the components of the three forces along each direction. Therefore:
- Along the x-direction:

- Along the y-direction:

So, the net force in component form is

B)
The magnitude of a vector F is given by Pythagorean's theorem:

where in this problem,
is the x-component
is the y-component
Substituting,

The direction instead is given by

where the negative sign means the direction is below the positive x-axis.
Learn more about vector addition:
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Explanation:
An Example of push as a force would be to push on a swing. The force moves the swing in a particular direction and the harder that you push the further the swing will go.
An example of pull as a force would be opening a door. ...
An example of pressure as a force is when you push down on a pile of grapes. is this what you mean
Here, F = m * a
F = m * v/t
Here, m = 81 Kg
v = 22 m/s
t = 1,4 s
Substitute their values,
F = 81 * 22/1.4
F = 81 * 15.71
F = 1273 N
So, Closest value from your options is 1300 N
In short, Your Answer would be Option B
Hope this helps!
Answer:
15 KJ
Explanation:
The quantity of heat (Q) required is given as:
Q = mcΔθ + mL
where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.
Given: m = 20g, temperature of ice = 0
, specific heat capacity of water = 4200 J/kg
, latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100
.
Q = m (cΔθ + L)
= 0.02(4200 x (100) + 330000)
= 0.02(420000 + 330000)
= 0.02 (750000)
Q = 15000
Q = 15000 Joules
Q = 15KJ
The quantity of heat needed to complete the conversion is 15 KJ.