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nekit [7.7K]
3 years ago
14

What is responsible for initiating a signal transduction pathway?

Physics
1 answer:
Komok [63]3 years ago
8 0

Answer:

The attachment of a signal molecule to a plasma membrane receptor.

Explanation:

The attachment of a signal molecule to a plasma membrane receptor initiates a signal transduction pathway.

Once the target cell receives the signal molecule it converts the signal to a form that can bring about a specific cellular response. This often occurs in a series of steps called a signal transduction pathway. Signal molecules bind to receptor protein, in cell membranes, and generally cause a conformational change in the proteins. This change in conformation is transmitted to the cytoplasmic domain or part of the receptor molecule. The transformed molecule interacts with the information-relaying molecules in the cytoplasm. These molecules are small molecules present in the cytoplasm known as secondary messengers. Calcium ions and Cyclic AMP (cAMP) are examples. This further starts a series of chain reactions, which ultimately reaches the target gene and causes its expression or repression.

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Need help as fast as possible please
DaniilM [7]
Regular reflections occurs when light reflects off a very smooth surface and forms a clear image.
Diffuse reflection: occurs when light reflects off a rough surface and forms a blurry image or no image at all.

Similarities: they both hit the surface, but the difference is one of them give clear image the other one gives blurry image or no image at all.

Hope this helped!
7 0
3 years ago
En una báscula hidráulica colocamos una persona de 75 kg sobre un émbolo y un camión de 7200 kg sobre una plataforma de 5 m de l
TEA [102]

...........................

4 0
4 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the
Over [174]

Answer:

Part a)

a= 0.32 m/s^2

Part b)

F_c = 3.6 N

Part c)

F_c = 5.5 N

Explanation:

Part a)

As we know that the friction force on two boxes is given as

F_f = \mu m_a g + \mu m_b g

F_f = 0.02(10.6 + 7)9.81

F_f = 3.45 N

Now we know by Newton's II law

F_{net} = ma

so we have

F_p - F_f = (m_a + m_b) a

9.1 - 3.45 = (10.6 + 7) a

a = \frac{5.65}{17.6}

a= 0.32 m/s^2

Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

F_c - F_f = m_b a

F_c = \mu m_b g + m_b a

F_c = 0.02(7)(9.8) + 7(0.32)

F_c = 3.6 N

Part c)

If Alex push from other side then also the acceleration will be same

So for box B we can say that Net force is given as

F_p - F_f - F_c = m_b a

9.1 - 0.02(7)(9.8) - F_c = 7(0.32)

F_c = 9.1 - 0.02 (7)(9.8) - 7(0.32)

F_c = 5.5 N

3 0
3 years ago
Batteries supply DC, direct current, which does not change in direction over time, though eventually they get exhausted.
SashulF [63]
My Anonymuos friend, I could not agree more with your statement.
Truer words have rarely if ever been expressed.
6 0
3 years ago
Calculate the distance moved by a runner who runs with a speed of 5 km/h for a period of 1.5 hours.
FrozenT [24]

Answer:

7.5 km

Explanation:

h5 per hour means that he traveled 5 km in 1 our. And then half of the hour, which means half an hour 5 km which is 2.5.

5 + 2.5 = 7.5

or just 1.5 x 5 = 7.5

8 0
3 years ago
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