<h3>
Answer:</h3>
46.67 m/s²
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of a rocket = 3 kg
- Force applied = 140 N
we are supposed to calculate the acceleration of the rocket;
- We are going to use the second Newton's law of motion;
- According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
- This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.
Therefore;
F = Ma
In this case;
Rearranging the formula
a = F ÷ m
= 140 N ÷ 3 kg
= 46.67 m/s²
Thus, the acceleration of the rocket is 46.67 m/s²
<span>a tendency to do nothing or to remain unchanged</span>
They transfer energy. Not sure what your choices are but this is a common question
It’s half the mass of the object by its velocity ^2
Answer:
F = 0.112 N
Explanation:
To find the magnitude of magnetic force on the wire, you use the following formula:
(1)
L: length of the wire = 200cm = 0.2m
i: current in the wire = 30 A
B: magnitude of the magnetic field = 0.055 T
θ: angle between the directions of L and B = 20°
You replace the values of L, i, B and θ in the equation (1):
hence, the magnetic force on teh wire is 0.112N
