I'm not sure what "60 degree horizontal" means.
I'm going to assume that it means a direction aimed 60 degrees
above the horizon and 30 degrees below the zenith.
Now, I'll answer the question that I have invented.
When the shot is fired with speed of 'S' in that direction,
the horizontal component of its velocity is S cos(60) = 0.5 S ,
and the vertical component is S sin(60) = S√3/2 = 0.866 S . (rounded)
-- 0.75 of its kinetic energy is due to its vertical velocity.
That much of its KE gets used up by climbing against gravity.
-- 0.25 of its kinetic energy is due to its horizontal velocity.
That doesn't change.
-- So at the top of its trajectory, its KE is 0.25 of what it had originally.
That's E/4 .
A heat engine is a device that uses heat to produce useful work.
To solve this problem we will apply the concepts related to the kinematic equations of linear motion. From there we will define the distance as the circumference of the earth (approximate as a sphere). With the speed given in the statement we will simply clear the equations below and find the time.



The circumference of the earth would be

Velocity is defined as,


Here
, then


Therefore will take 167463.97 s or 1 day 22 hours 31 minutes and 3.97seconds
Answer:
The distance is
.
Explanation:
Given that,
Time 
The velocity is no more than a 14 % error in the speed of light.
So,
Velocity 
We need to calculate the distance
Using formula of speed


Where, v = speed
d = distance
t = time
Put the value into the formula


We know that,
The one side distance d' is



Hence, The distance is
.