Answer:
The probability that the intersection will come under the emergency program is 0.1587.
Step-by-step explanation:
Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.
Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.
For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.
Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).
The values of 
, the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program
what is this
Step-by-step explanation:
Option #1 – charges 5% simple interest per year; this is a short-term loan for only 5-years.
Option #2 – charges 7% simple interest per year; this is a short-term loan for only 3-years.
Option #3 – charges 3.2% simple interest per year; there is no time limit on this loan (as a group determine how long you think it will take you to make enough money to be able to pay back the loan with interest)
Option #4 - charges 10% simple interest per year; only lasts 10 months
Option what is this
Answer:
<em>The employees will work for 1 hour, will earn $5 per hour and will be paid $5</em>
Step-by-step explanation:
<u>System of Equations</u>
The number of hours the employees work is x.
And the hourly wage that they are paid is y. The store manager is willing to pay the employees a wage given by the equation
10y-30x=20
The business owner states that the employees should be paid a wage given by the equation
6y+30x=60
Adding both equations we have:
16y = 80
Dividing by 16:
y = 80/16 = 5
Substituting into the first equation:
10*5-30x=20
Operating and simplifying:
50-30x=20
50 - 20 = 30x
30x = 30
x = 30/30 = 1
Thus, the employees will work for 1 hour, will earn $5 per hour and will be paid $5
Answer: x+8
Step-by-step explanation:
