<span>A polynomial with the given zeros can be represented as
f(x) = (x-1)(x-2)(x+2)(x+3).
Note that if you set f(x) = 0, then 1,2,-2, and -3 certainly are the solutions. From here, we simply multiply/expand out the polynomial. We can do this in a variety of ways, one of which is taking the left two and right two products separately. We have
(x-1)(x-2) = x^2 - 3x + 2
and
(x+2)(x+3) = x^2 + 5x + 6.
This gives that
f(x) = (x^2 - 3x + 2) (x^2 + 5x + 6).
Expanding this expression out then gives us our answer as
f(x) = x^4 + 2x^3 - 7x^2 - 8x + 12
or answer choice B.</span>
Answer:
13.1148770486
.....................,...
Answer:
(x+1)^2 = 49
x = 6 x = -8
Step-by-step explanation:
x^2 + 2x – 48 = 0
Add 48 to each side
x^2 + 2x =48
Take the coefficient of x
2
Divide by 2
2/2=1
Square it
1^2 =1
x^2 + 2x +1=48+1
x^2 +2x+1 = 49
(x+1)^2 = 49
Take the square root of each side
sqrt((x+1)^2) =±sqrt( 49)
x+1 = ±7
Subtract 1 from each side
x+1-1 = -1 ±7
x = -1+7 x = -1 -7
x = 6 x = -8
Answer:
12 trades
Step-by-step explanation:
Let's call 'x' the number of trades they will do.
After each trade, the number of cards Ian has increase by 1 (he gives 1 but receives 2), and the number of cards Jason has decrease by 1 (he receives 1 but gives 2), so after x trades, the number of cards Ian has is 20 + x, and Jason has 44 - x.
To find the number of trades when they will have the same amount of cards, we have that:
20 + x = 44 - x
2x = 24
x = 12 trades
Answer:
c
Step-by-step explanation:
