There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
The measures of the angles are 59 degrees
<h3>How to determine the value of the angles?</h3>
The angles are given as:
Angle 1 = 2x + 17
Angle 2 = 3x - 4
By the interior angle theorem, the angles are congruent
So, we have
Angle 1 = Angle 2
Substitute the known values in the above equation
2x + 17= 3x - 4
Collect the like terms
3x - 2x = 17 + 4
Evaluate the like terms
x = 21
Substitute x = 21 in Angle 1 = 2x + 17
Angle 1 = 2 * 21 + 17
Evaluate
Angle 1 = 59
This means that
Angle 1 = Angle 2 = 59
Hence, the measures of the angles are 59 degrees
Read more about angles at:
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Answer:
S1 is congruent to S2
Step-by-step explanation:
3*25=75
so the question is 75/8
you would 10 packages since
8*8=64
8*9=72
but 8*10=80 is enough, remainder 5
