Which answer choice below correctly represents the quotient of 846 = 35?

PLEASE HELP ASAP I can’t fail this

MArishka [77]

Answer:

-5,5

5,5

Step-by-step explanation:

8 0

3 years ago

Suppose the number of free throws in a basketball game by one player are normally distributed with a standard deviation 0.97 fre

babunello [35]

Answer: 1.960

Step-by-step explanation:

The value of z we use to calculate a confidence interval with a ( $1-\alpha$ ) confidence level is a two-tailed test value i.e. represented by :-

$z_{\alpha/2}$

Given : The level of confidence: $1-\alpha=0.95$

Then, significance level : $\alpha: 1-0.95=0.05$

With the help of standard normal distribution table for z , we have

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.960$

Hence, the value of z should be used to calculate a confidence interval with a 95% confidence level =1.960

3 0

4 years ago

721 + 19 = 886 + 33 - 447 22= 915 + 36 = ??

timama [110]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help ASAP!!!! Which type of transformation is shown ?

NikAS [45]

Answer:

you have to do it yourself

4 0

3 years ago

16. A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours

Reika [66]

Answer:

a) 23.11% probability of making exactly four sales.

b) 1.38% probability of making no sales.

c) 16.78% probability of making exactly two sales.

d) The mean number of sales in the two-hour period is 3.6.

Step-by-step explanation:

For each phone call, there are only two possible outcomes. Either a sale is made, or it is not. The probability of a sale being made in a call is independent from other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours, find:

Six calls per hour, 2 hours. So

$n = 2*6 = 12$

Sale on 30% of these calls, so $p = 0.3$

a. The probability of making exactly four sales.

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{12,4}.(0.3)^{4}.(0.7)^{8} = 0.2311$

23.11% probability of making exactly four sales.

b. The probability of making no sales.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138$

1.38% probability of making no sales.

c. The probability of making exactly two sales.

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678$

16.78% probability of making exactly two sales.

d. The mean number of sales in the two-hour period.

The mean of the binomia distribution is

$E(X) = np$

So

$E(X) = 12*0.3 = 3.6$

The mean number of sales in the two-hour period is 3.6.

4 0

3 years ago