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Rus_ich [418]
2 years ago
10

Please help! What is the perimeter of Trapezoid? (ABCD) Answer and explanation please! <3

Mathematics
1 answer:
viktelen [127]2 years ago
4 0

Answer:

are there any numbers around it?

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Which number line represents the solution set for the inequality -4(x + 3) S-2 - 2x?
Basile [38]

Answer:

Which number line represents the solution set for the inequality -4(x + 3) S-2 - 2x?

-7 -6 -5 -4 -3 -2 -1 0

1

2

3

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5

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7

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-7 -6 -5 -4 -3 -2 -1 0

+

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0 1 2

Step-by-step explanation:

5 0
3 years ago
What multiplier do we use to increase by 72%
Deffense [45]

Answer:

1.72

Step By Step:                                

5 0
3 years ago
Divide 30 in a ratio of 3:2
Sergeeva-Olga [200]
Other\ method:\\\\x;y-searches\\\\  \left\{\begin{array}{ccc}x+y=30&|subtract\ y\ from\ both\ sides\\x:y=3:2\end{array}\right\\\left\{\begin{array}{ccc}x=30-y&(1)\\\frac{x}{y}=\frac{3}{2}&(2)\end{array}\right\\\\subtitute\ (1)\ to\ (2):\\\\\frac{30-y}{y}=\frac{3}{2}\ \ \ \ |cross\ multiply\\\\(3)(y)=(2)(30-y)\\3y=60-2y\ \ \ \ |add\ 2y\ to\ both\ sides\\5y=60\ \ \ \ |divide\ both\ sides\ by\ 5\\\boxed{y=12}

Put\ the\ value\ of\ y\ to\ (1):\\x=30-12\\\boxed{x=18}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=18\\y=12\end{array}\right\to18:12}
4 0
3 years ago
Read 2 more answers
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6
USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

The coordinates are given as:

\mathbf{(x,y) = (-60,0)\ (60,0)}

The center of the hyperbola  is  

\mathbf{(h,k) = (0,0)}

The distance from the center to the focal points is given as:

\mathbf{c = 60}

Square both sides

\mathbf{c^2 = 3600}

The distance from the receiver to the transmitters  is given as:

\mathbf{2a = 100}

Divide both sides by 2

\mathbf{a = 50}

Square both sides

\mathbf{a^2 = 2500}

We have:

\mathbf{b^2 = c^2 - a^2}

This gives

\mathbf{b^2 = 3600 - 2500}

\mathbf{b^2 = 1100}  

The equation of an hyperbola is:

\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}

So, we have:

\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}

\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Hence, the equation of the hyperbola is: \mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}

Read more about hyperbolas at:

brainly.com/question/15697124

7 0
2 years ago
Read 2 more answers
Please solve this, i need help on a test :)
musickatia [10]

Answer:

b = 5

Step-by-step explanation:

28.95 + 34b ≤ 200

34.05b ≤ 200 - 28.95

34.05b ≤ 171.05

b ≤ 5.023

b = 5 is the answer

check: 5 * 34.05 + 28.95 = 199.2

if b=6: 6 * 34.05 + 28.95 = 233.25

6 0
2 years ago
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