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3 years ago

4 / 7 * 2 / 3 * *9/16

1 answer:

4 0

$\bf \cfrac{4}{7}\cdot \cfrac{2}{3}\cdot \cfrac{9}{16}\implies \cfrac{4}{16}\cdot \cfrac{9}{3}\cdot \cfrac{2}{7}\implies \cfrac{1}{4}\cdot \cfrac{3}{1}\cdot \cfrac{2}{7}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{2}{4}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{1}{2}\\\\\\\cfrac{1\cdot 3\cdot 1}{7\cdot 1\cdot 2}\implies \cfrac{3}{14}$

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sineoko [7]

Answer:

The first image is an Isosceles Triangle and Acute

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2 years ago

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100 POINTS TO RIGHT AWNSER!!!!

makvit [3.9K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586

——————————

The answer is option D) r < 5 or r > – 1.

I'm going to graph each inequality below on a number line.

A) r > 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

The result is found just by joining those two intervals together. Actually that compound inequality only implies

r > – 1

which does not represent all real numbers.

—————

B) r > 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r5~~or~~r$

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.

—————

C) r < 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r$

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.

—————

D) r < 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

Now all real numbers are included in the union. So this is the right choice.

Answer: option D) r < 5 or r > – 1.

I hope this helps. =)

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2 years ago

Find the value of x<br>9.10.12,x, 20.25 ; The median is 14.

Elodia [21]

Answer: 16

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9,10,12,x ,20, 25 so we know the median is 14 which is the middle number.

Since the numbers are 6 it means there will be 2 middle numbers and if you divide them it will be 14.

we know one of the middle numbers is 12 and we trying to find x .

So we could use the equation x + 12 = 2(14)

x + 12 = 28

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x= 16 so X is 16. check: 16+12=28/2 is 14.

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2 years ago

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mihalych1998 [28]

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Step-by-step explanation:

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2 years ago

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Answer:

2 and 1/4

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