I'll mark brainliest!

Mathematics

1 answer:

GuDViN [60]3 years ago

4 0

Answer:

im answering so he can have it :D

Step-by-step explanation:

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Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, connuing un

jonny [76]

Answer:

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

Step-by-step explanation:

It is said that Actuary Rahul examines a low risk policy

Probability of a low risk policy having a claim = 10% = 0.1

Actuary Toby examines high risk policy

Probability of a high risk policy having a claim = 20% = 0.2

Let the number of policies examined by actuary Rahul before he finds a claim and stop be n

Probability that actuary Rahul examines exactly n policies = $0.9^{n-1} (0.1)$

Probability that Toby examines more than n policies = $0.8^n$

Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = $0.9^{n-1} (0.1) (0.8)^n$

probability that both events happen simultaneously = $\frac{0.1}{0.9} (0.72^{n})$

The probability that Actuary Rahul examines fewer policies that Actuary Toby = $\sum\limits^ \infty_1 {\frac{0.1}{0.9} 0.72^{n} }$ = $\frac{1}{9}\sum\limits^ \infty_1 { 0.72^{n} } = \frac{1}{9} (\frac{0.72}{1-0.72} ) = \frac{1}{9} (\frac{0.72}{0.28} )$