y= mx+b
(16, -7) = (x,y)
2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y
2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2
Insert the values into y = mx + b
solve for m and then solve for b
Answer:
Its A.
Step-by-step explanation:
I just finsihed that question.
Answer:
x = - 3 and x = 1
Step-by-step explanation:
Given the rational expression

The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Thus x = 1 and x = - 3 are both excluded values
Answer:
Step-by-step explanation:
can you show a picture?