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yawa3891 [41]
3 years ago
13

Whats the answer A.B.C.D

Mathematics
1 answer:
natka813 [3]3 years ago
7 0
What do you mean??????
there is no question...
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There are 22 total fish in the tank because 8 got doubled so 11 would also have to get doubled
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Evaluate the expression. check all possible sets that the solution may belong in. 40-5^2
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15

Step-by-step explanation:

following PEMDAS, we don't have () so we move on to exponents

5^2 is equal to 5 x 5 which is 25

40-25=15

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4 years ago
A certain type of automobile battery is known to last an average of 1140 days with a standard deviation of 80 days. If 400 of th
Sever21 [200]

Answer:

Mean = \mu = 1140

Standard deviation = \sigma = 80

Find the probabilities for the average length of life of the selected batteries.

A)The average is between 1128 and 1140.

We are supposed to fidn P(1128<x<1140)

Formula : Z=\frac{x-\mu}{\sigma}

At x = 1128

Z=\frac{1128-1140}{80}

Z=-0.15

Refer the z table for p value

P(x<1128)=0.4404

At x = 1140

Z=\frac{1140-1140}{80}

Z=0

Refer the z table for p value

P(x<1140)=0.5

So,P(1128<x<1140)=P(x<1140)-P(x<1128)=0.5-0.4404=0.0596

Hence the probabilities for the average length of life of the selected batteries  is between 1128 and 1140 is 0.0596

B)The average is greater than 1152.

P(x>1152)

At x = 1128

Z=\frac{1152-1140}{80}

Z=0.15

Refer the z table for p value

P(x<1152)=0.5596

So,P(x>1152)=1-P(x<1152)=1-0.5596=0.4404

Hence the probabilities for the average length of life of the selected batteries is greater than 1152 is 0.4404

C) The average is less than 940.

P(x<940)

At x = 940

Z=\frac{940-1140}{80}

Z=-2.5

Refer the z table for p value

P(x<940)=0.5596

Hence the probabilities for the average length of life of the selected batteries is less than 940 is 0.5596

7 0
3 years ago
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