First: Replace “x” with its known value. Since x = 3, plug it into the formula.
• F(3) = 6^3
Second: Solve the formula.
• 6^3 = 6 x 6 x 6 = 216
• F(3) = 216
The sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) in our case:
s(n)=3(1-4^n)/(1-4)
s(n)=-(1-4^n)
s(n)=(4^n)-1 and s=1023
(4^n)-1=1023
4^n=1024
n ln4=ln1024
n=(ln1024)/(ln4)
n=5
Answer:
Step-by-step explanation:
x^2-10x+21
(x-7)(x-3)
find the 2 numbers that when multiplied make the last number or +21 and when combined make the middle number of -10. -7*-3 = 21 and -7+-3=10
When you multiple fractions, you just multiple numerators and denominators.
10 / 7 × 3 / 8 = (10 × 3) / (7×8) = 30 / 56
Now reduce the fraction:
30 / 56 = <span>15/28
Final answer: </span><span>15/28</span>
