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Nookie1986 [14]
3 years ago
5

Please Hurry Need Answer -2/5 + 4/5

Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

2/5

Step-by-step explanation:

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i used the answer key to get my answer and checked it with my dumb useless teacher and it’s right but, he won’t tell me how to g
gizmo_the_mogwai [7]
You multiply it with the same number you use for the denominator.
in this case 3/4 and 7/10
you find the LCM of the denominator is 20
so for 4 to become 20 you multiply by 5 then for the numerator 3 also multiply by 5, so you get 15/20
its the same also with 7/10, you multiply both the numerator and the denominator by 2 and get 14/20
hope it help... :)




7 0
3 years ago
PLEASE HELP 100 POINTS 100 100 100 PLEASSSSE
Oksi-84 [34.3K]

Answer:

b

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
(5x+5) (6x-1) solve for x
Nitella [24]
The answer for x is x=6 sorry if I’m wrong
3 0
3 years ago
Read 2 more answers
Determine the greatest common divisor of the elements of the set \[ s = \{ n^{13} - n \mid n \in \mathbb{z} \}. \]
Kay [80]

Answer:

2730

Step-by-step explanation:

We want to determine the greatest common divisor of the elements of the set  S = \{ n^{13} - n \mid n \in \mathbb{Z} \}.

We apply the Fermat's little theorem which states that if p is a prime number, then for any integer a, the number aᵖ − a is an integer multiple of p.

Now, n^{13} \equiv n \mod p if p-1 divides 12.

Since the  of 12 are 1,2,3,4, 6, 12, the corresponding primes are 2, 3, 5, 7, 13.

Therefore, the gcd of the elements in 2^{13}-2 and 3^{13}-3$ is 2 \cdot 3 \cdot 5 \cdot 7 \cdot 13.

2*3*5*7*13=2730

Therefore, the gcd of the elements in set S is 2730.

5 0
3 years ago
Select the correct answer,
krok68 [10]
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4 0
2 years ago
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