How do you solve this problem?
1 answer:
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Yo sup??
The two triangles are similar by AAA property ie
Angle Angle Angle property
Let us name the two triangles as ABC and DEF
By observing the figure
mB=mE=90 (right angled triangle)
mA=mD (parallel lines property)
mC=mF (parallel lines property)
Therefore by AAA the two triangles are similar .
The diagram is given below.
PS: All the credits for image goes to Picasso-PSN03
