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kolbaska11 [484]
3 years ago
13

From 77 to 116 what’s the percentage increase

Mathematics
1 answer:
podryga [215]3 years ago
4 0
50.65%
Take the difference between the final value and initial value then divide it by the initial value to get a decimal answer. Multiply it by 100 to get it in percentage terms.

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Write the equation of a line with that passes through the<br> points (-3, -2) and (6,1)?
True [87]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

: Y = 1/3x - 1

:

M = y2 - y1/ x2-x1

M = 6 - (-3) / 1 - (-2)

Y = 1/3x + b

Then substitute one of the points into the equation

-2= 1/3(-3) + b

-2 + 2 + b = 1/3(-3) +b - b + 2

-b = 1/3(-3) + 2

-b = 1

b = -1

Y = 1/3x - 1

Then i plugged it into

!

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5 0
3 years ago
Sheryl has a basket of ripe apples and peaches. The number of apples in the basket is 12 more than twice the number of peaches.
saveliy_v [14]

Answer=12

Step-by-step explanation:

well if there are 36 apples and there are 12 more apples then peaches then 36-12= 24 24/2=12  

4 0
3 years ago
Find the value of u to the nearest tenth.
Ket [755]

Answer:

its 10.049 id.k what to round it 2 tho

Step-by-step explanation:

5 0
3 years ago
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Rita has 3 ¾ cups of potato chips to share with 6 friends. How many cups does EACH friend get?
Nikitich [7]

Answer:

5/8

Step-by-step explanation:

6 0
3 years ago
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Here we will study the function f (x) = e ^ x sin (x), where x ∈ [0, 2π]. a) Determine where the function is decreasing and incr
Semmy [17]

fff

f(x) = e^x sin (x)

To find increasing and decreasing intervals we take derivative

f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)

Now we set the derivative =0  and solve for x

e^x(sinx+cosx)=0

sinx + cosx =0

divide whole equation by cos x

\frac{sinx}{cosx} + \frac{cosx}{cosx} =0

tanx +1 =0

tanx = 1

x=\frac{3\pi }{4} and  x=\frac{7\pi}{4}

Now we pick a number between 0 to  \frac{3\pi }{4}

Lets pick  \frac{\pi }{2}

Plug it into the derivative

f'(x) =e^{\frac{\pi }{2}}(sin(\frac{\pi}{2})+cos(\frac{\pi }{2}))

= 4.810 is positive

So the graph of f(x) is increasing on the interval [0, x=\frac{3\pi }{4})

Now we pick a number between   \frac{7\pi}{4} to 2pi

Lets pick  \frac{11\pi}{6}

Plug it into the derivative

f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))

= 116 is positive

So the graph of f(x) is increasing on the interval (\frac{7\pi }{4}, 2\pi)

Increasing interval is (0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)

Decreasing interval is (\frac{3\pi}{4}, \frac{7\pi}{4})

(b)

The graph of f(x) increases and reaches a local maximum at x=\frac{3\pi}{4}

The graph of f(x) decreases and reaches a local minimum at x=\frac{7\pi}{4}

(c)

f(0) = 0

f(2\pi)=0

f(\frac{3\pi }{4})=7.46

f(\frac{7\pi}{4})=-172.64

Here global maximum at x=\frac{3\pi}{4}

Here global minimum at x=\frac{7\pi}{4}


3 0
3 years ago
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