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Sholpan [36]
2 years ago
15

What is the quotient of 2 ÷ 2/3?​

Mathematics
2 answers:
Aleksandr [31]2 years ago
4 0
Hello! Step by step divide 2 by 2/3 which is 2 so

1
.3=
2.3

1*2
=6

2
= 2*3

2*1
=3

Dividing the two fractions is like multiplying the first fraction by value or reciprocal value of first fraction value of SECOND fraction. So find the reciprocal like reversing the numerator and denominator reciprocal of 2/3 is 3

Of the second fraction then multiply the two numerators. Again multiply the two decnominators so the next following step intermediate step canceling by a comma factor 2 gives 3.... in words- two divided by two thirds=three

Hope that helps!!! Answer=3
Neko [114]2 years ago
3 0

Answer:

The answer is 3! I believe.

Step-by-step explanation:

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If 2x• 3x +(2•3 )x +6x= 648, find x.
klasskru [66]

Answer:

x = -1 ± √109

Step-by-step explanation:

2x • 3x + (2 • 3)x + 6x = 648

According to PEMDAS (parentheses/exponents | multiplication/division | addition/subtraction), we should solve the parentheses first.

(2 • 3) = 6

Now we have:

2x • 3x + (6)x + 6x = 648

Now let's multiply.

2x • 3x = 6x²

6 • x = 6x

Now we have.

6x² + 6x + 6x = 648

Combine like terms.

6x² + 12x = 648

Let's factor out a 6.

6(x² + 2x) = 648

Divide both sides by 6.

x² + 2x = 108

Let's use completing the square.

Our equation is in a² + bx = c form.

Divide b by 2.

2/2 = 1

Then square it.

1² = 1

Add 1 to both sides.

x² + 2x + 1 = 108 + 1

Simplify.

x² + 2x + 1 = 109

Now we want to factor the left side. A shortcut is just to use b/2.

(x + 1)² = 109

Take the square root of both sides.

x + 1 = ±√109

The square root is as simplified as possible.

Subtract 1 from both sides.

x = -1 ± √109

Hope this helps!

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3 years ago
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RideAnS [48]

Answer:

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Step-by-step explanation:

3 0
2 years ago
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Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
2 years ago
Hello, if you’re feeling generous today please lend a hand!! thank you
andrew11 [14]

Answer:

x  \leqslant 2

Step-by-step explanation:

The point is shaded which means its is equal to and since the arrow goes to the left it is less than. Therefore x is less than or equal to 2

3 0
3 years ago
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Math class ends at 10:35 am
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