The radius of the cardboard tube of 85th loop of paper is 4.92cm
The arithmetic sequence is the sequence where every term is increased or decreased by a fixed number from the previous number.
Here the outer radius of the tube is 2.4 cm
the thickness of the paper is 0.3mm= 0.03cm
i.e. in every loop the increase in the radius of the loop is 0.03cm
then the radius in every sequence will be 2.40, 2.43, 2.46, 2.49, 2.52, .....
so here it is clear that it is an arithmetic sequence with a common difference of 0.03.
nth term of the sequence, aₙ = a₁ + (n - 1)d where a₁ is the first term, n is the index of the loop, and d is a common difference.
here a₁ =2.40
d=0.03
n=85
the radius of tube of the 85th loop will be= r= 2.40+(85-1)0.03= 2.40+ 2.52= 4.92
Therefore The radius of the cardboard tube of the 85th loop of paper is 4.92cm
Learn more about the arithmetic sequence
here: brainly.com/question/6561461
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By definition, an isosceles triangle has 2 of the 3 sides with the same length. From this, we already know that the third side must be or 5 or 12.
We also know that, for every triangle, the sum of two sides must be always bigger than the third side, for any combination.
From this second affirmation, we know that the third side can not be 5, because:
From this, we conclude that the third side of an isosceles triangle with sides equal to 5 and 12 is equal to 12.
Answer:
⟨3, –5⟩ and ⟨6, –10⟩
Step-by-step explanation:
⟨3, –5⟩ cross ⟨6, –10⟩ = 0
⟨2, –3⟩ cross ⟨9, –6⟩ = 15
⟨–2, 3⟩ cross ⟨–6, –4⟩ = 26
⟨–5, 4⟩ cross ⟨–4, –2⟩ = 26
⟨3, –5⟩ and ⟨6, –10⟩
Answer:
One solution
Step-by-step explanation:
