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Evgesh-ka [11]
3 years ago
8

Pleaseee answer quickly

Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

4.  3 units

5. Triangle  

6.  (0,2)

Step-by-step explanation:

4. The distance between the x axis and the point (8,3) is 3 units

5. Triangle  will be formed if the points A(-3, 0), B (0,3) and C (3,0) are joined together

6. Since the point lie on the y-axis, its x co-ordinate will be zero and the point will be (0,2)

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Simplify the polynomial(-8×)+×+(-2×)​
Morgarella [4.7K]

Answer:

-9x

Step-by-step explanation:

Without the confusing parentheses, this "polynomial" becomes -8x + x -2x. If we take 2 away from -8, it becomes -10. If we add a positive x, it becomes -9x. Therefore, the answer is (the monomial) -9x.

8 0
3 years ago
Read 2 more answers
Can Somebody help me real fast?
ioda

Answer:

23 21

Step-by-step explanation:

4 0
3 years ago
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Perform the following division: (–1/6) ÷ (–3/7) A. –7/18 B. 7/18 C. –3/42 D. 3/42
Crank

Answer:

B. 7/18

Step-by-step explanation:

(-1/6)/(-3/7)

= -1/6 * -7/3

= -1*-7/6*3

= 7/18

(pls give brainliest)

3 0
3 years ago
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Find an equation of the circle that has center (-1,6) and passes through (-6,1)
horsena [70]

Answer:

(x + 1)² + (y - 6)² = 50

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius.

The radius is the distance from the centre to a point on the circle.

Calculate r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (- 1, 6) and (x₂, y₂ ) = (- 6, 1)

r = \sqrt{(-6+1)^2+(1-6)^2}

  = \sqrt{(-5)^2+(-5)^2}

  = \sqrt{25+25}

  = \sqrt{50}

(h, k ) = (- 1, 6 ), then

(x - (- 1))² + (y - 6)² = (\sqrt{50} )² , that is

(x + 1)² + (y - 6)² = 50 ← equation of circle

3 0
3 years ago
Can you help solve this problem
Serhud [2]
My method is on a) you would just subtract 12 and 7 which is 5. You can do the rest and then when you get all the answers put them from smallest to largest
7 0
3 years ago
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