Answer:
158.4 pounds
Step-by-step explanation:
first find the volume of the tank
to convert this to m^3 we know that 1m = 100cm
the cm^3 cancel out.
by simply converting the side-lengths to meters beforehand can give you this answer directly:
it is given that 1 meter cube of water weighs about 2200 pounds.
multiply both sides with 0.072 to find our answer:
hence the weight of the water in the tank would be 158.4 pounds!
the answer is 4.36yds. 4.36 ×4.36= 19.006
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
2^m=2^n take the natural log of both sides
m*ln2=n*ln2 divide both sides by ln2
m=n
