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Drupady [299]
2 years ago
12

10.B. What number do you need to add/subtract/multiply/divide each side by in

Mathematics
1 answer:
Sindrei [870]2 years ago
5 0

Step-by-step explanation:

step 1. m + 7.02 = 6.32

step 2. m = -0.70. (subtract 7.02 from each side)

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Costs are rising for all kinds of medical care. The mean monthly rent at assisted-living facilities was reported to have increas
polet [3.4K]

Answer:

a) The 90% confidence interval estimate of the population mean monthly rent is ($3387.63, $3584.37).

b) The 95% confidence interval estimate of the population mean monthly rent is ($3368.5, $3603.5).

c) The 99% confidence interval estimate of the population mean monthly rent is ($3330.66, $3641.34).

d) The confidence level is how sure we are that the interval contains the mean. So, the higher the confidence level, more sure we are that the interval contains the mean. So, as the confidence level is increased, the width of the interval increases, which is reasonable.

Step-by-step explanation:

a) Develop a 90% confidence interval estimate of the population mean monthly rent.

Our sample size is 120.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 120-1 = 119

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.90}{2} = \frac{0.10}{2} = 0.05

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 119 and 0.05 in the t-distribution table, we have T = 1.6578.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{650}{\sqrt{120}} = 59.34

Now, we multiply T and s

M = T*s = 59.34*1.6578 = 98.37

The lower end of the interval is the mean subtracted by M. So it is 3486 - 98.37 = $3387.63.

The upper end of the interval is the mean added to M. So it is 3486 + 98.37 = $3584.37.

The 90% confidence interval estimate of the population mean monthly rent is ($3387.63, $3584.37).

b) Develop a 95% confidence interval estimate of the population mean monthly rent.

Now we have that \alpha = 0.95

So

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

With 119 and 0.025 in the t-distribution table, we have T = 1.9801.

M = T*s = 59.34*1.9801 = 117.50

The lower end of the interval is the mean subtracted by M. So it is 3486 - 117.50 = $3368.5.

The upper end of the interval is the mean added to M. So it is 3486 + 117.50 = $3603.5.

The 95% confidence interval estimate of the population mean monthly rent is ($3368.5, $3603.5).

c) Develop a 99% confidence interval estimate of the population mean monthly rent.

Now we have that \alpha = 0.99

So

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.005

With 119 and 0.025 in the t-distribution table, we have T = 2.6178.

M = T*s = 59.34*2.6178 = 155.34

The lower end of the interval is the mean subtracted by M. So it is 3486 - 155.34 = $3330.66.

The upper end of the interval is the mean added to M. So it is 3486 + 155.34 = $3641.34.

The 99% confidence interval estimate of the population mean monthly rent is ($3330.66, $3641.34).

d) What happens to the width of the confidence interval as the confidence level is increased? Does this seem reasonable? Explain.

The confidence level is how sure we are that the interval contains the mean. So, the higher the confidence level, more sure we are that the interval contains the mean. So, as the confidence level is increased, the width of the interval increases, which is reasonable.

4 0
3 years ago
At the end of each year, Carl and Linda Munson will deposit $2,100 into a 401k retirement account.
Ira Lisetskai [31]

Answer:

$22680

Step-by-step explanation:

HOPE IM CORRECT BEEN A WHILE SINCE IVE DONE THIS!

4 0
3 years ago
Read 2 more answers
Royce has $15 with him and spends $12 to buy his favorite comics. He has $3 left, which he deposits in the bank. Which number wi
Sonja [21]

Answer:

C: +3

Step-by-step explanation:

We know this because Royce added money to his bank account, not subtract (b). The other options are just there to confuse you.

I hope this helps!!

6 0
3 years ago
Read 2 more answers
2 3/4+3 5/8 simplified
otez555 [7]

2\frac{3}{4}+3 \frac{5}{8}=6\frac{3}{8}

Solution:

Given expression is 2\frac{3}{4}+3 \frac{5}{8}.

To simplify the expression 2\frac{3}{4}+3 \frac{5}{8}.

Let us first convert the mixed fraction into improper fraction.

2\frac{3}{4}+3 \frac{5}{8}=\frac{(2\times 4) + 3}{4}+ \frac{(3 \times 8)+5}{8}

            =\frac{8+ 3}{4}+ \frac{24+5}{8}

            =\frac{11}{4}+ \frac{29}{8}

Take LCM for the denominators (LCM of 4, 8 = 8) and make the same.

            =\frac{11\times2}{4\times 2}+ \frac{29\times1}{8\times1}

            =\frac{22}{8}+ \frac{29}{8}

            =\frac{51}{8}

Now, divide 51 by 8 and again write it in the mixed fraction.

             =6\frac{3}{8}

2\frac{3}{4}+3 \frac{5}{8}=6\frac{3}{8}

Hence, the simplified answer is 6\frac{3}{8}.

7 0
3 years ago
Plz help me with number 1 and 2 plz asp
frozen [14]
1. D

2. B

Hope it helps!
5 0
3 years ago
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