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3 years ago

Whoever gets this right i will put them as brainliest?

Mathematics

2 answers:

frutty [35]3 years ago

6 0

Answer:

Step-by-step explanation:

-2 - 6 equals -8.

PLZ MARK BRAINLIST AND RATE THIS

motikmotik3 years ago

4 0

Answer:

Is it c?

Step-by-step explanation:

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Find the cube roots of unity in standard form (a+bi). Use exact values.

Marina86 [1]

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7 0

3 years ago

Explain how you can find the LCM of 8 and 10

lions [1.4K]

Answer:

Step-by-step explanation:

When trying to find the LCM of two numbers you need to write down all possible ways to multiply any number used to get both 8 and 10. When doing that, the LCM is the smallest number out of both of them.

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4 years ago

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PLEASE HELP!!!!⚠️ the last equation is “3/5x=12” if you can answer that as well thank you.

navik [9.2K]

Answer:

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Step-by-step explanation:

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3 years ago

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Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

2 years ago

What is the solution to the equation? 2/3 x =10 A.15 B.30 C.6 1/2 D.6 2/3

attashe74 [19]

2/3 x=10
Multiply 3*(2/3 x)=3*10
2x=30
x=15
A is the answer

7 0

3 years ago