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3 years ago

9

Please help!! :) Will give brainliest!

1 answer:

stich3 [128]3 years ago

7 0

Answer is A
144 + 12y + y^2

if perfect square should be
144 + 24y + y^2

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7.167×10 with the power of 6

Dafna1 [17]

I think the answer is 716.7 not 100% positive

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2 years ago

08- O ponto de encontro do eixo x com eixo y , indicado pelo par ordenado ( 0;0) . É Chamado de : *

skad [1K]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

sallys cup cake shop sold a total of 63 cupcakes yesterday and 32 of those had sprinkles how many cupcakes were sold without spr

lianna [129]

Answer:

31

Step-by-step explanation:

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3 0

3 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

2 years ago

Read 2 more answers

Jack recieved $600 for his birthday. If he saves it in a bank account with 8% interest compounded yearly, how much money will he

Gwar [14]

so 21 - 13, the money will be invested for 8 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$600\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\to &1\\ t=years\to &8 \end{cases} \\\\\\ A=600\left(1+\frac{0.08}{1}\right)^{1\cdot 8}\implies A=600(1.08)^8\implies A\approx 1110.558126$

8 0

2 years ago