Solve. x + 6/7 = 3^2/9 x = 23/63 x = 1^ 7/16 x = 2^ 23/63 x = 4^ 5/ 63
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The major axis of the eclipse is 12 units long
The given parameters can be represented as:
See attachment for illustration
To solve this question, we make use of the following theorem
The distance between a point and the foci sums up to the major axis
This translates to:
