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ludmilkaskok [199]
3 years ago
14

What are the solutions of the equation?15 - 8x^2 – 14x​

Mathematics
1 answer:
ipn [44]3 years ago
6 0
One solution to your problem is 15(1-2x)
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Amara needs 4545 kilograms of meat to feed her 22 pet dragons each day. Each pet dragon eats the same amount of meat. How many k
max2010maxim [7]

Answer:

9090 kilograms

Step-by-step explanation:

To find the number of kilograms per dragon, we divide the amount of meat by the number of dragons.

4545/22  kilograms per dragon

Now we can multiply by the 44 dragon that she has.

4545/22 * 44 = 9090 kilograms

3 0
2 years ago
Read 2 more answers
What is .40 = .25 X​
leva [86]

Answer:

x=1.6

Step-by-step explanation:

.40=.25x

you move .25 to the other side which would look like this .40/.25=x and then you solve for x, which you would get 1.6.

5 0
3 years ago
Determine if the sequence is geometric.
Nikolay [14]
THE SEQUENCE IS GEOMETRIC
3 0
3 years ago
Use slopes and y-intercepts to determine if the lines 5x-5y=-2 and -x+2y=4
HACTEHA [7]

The given pair of lines are not perpendicular.

<h3>What is a line?</h3>

The line is a curve showing the shortest distance between 2 points.

5x - 5y = -2 - - - - - (1)
Transform the equation into standard form,
5x + 2 = 5y
y = 5x /5 + 2/5
y = x + 2/5


The slope of equation 1 is m_1 = 1  and intercept c = 2 / 5


Similarly
x + 2y = 4    - - - - - - - -(2)
Transform it into standard form
y = -x/2 + 4 /2
y = -x / 2 + 2


Slope of the equation 2  m_2= -1 / 2 and intercept c = 2
Slope of line 1 * slope of line 2 = 1 * -1/2 = -1/2


Since the lines are not perpendicular because the pair of lines does not satisfy the property of perpendicular lines i.e
m_1*m_2 = -1

Thus, the given pair of lines are not perpendicular.

Learn more about lines here:

brainly.com/question/2696693

#SPJ1  

6 0
1 year ago
How can I determine the question I circled? I’m stuck, please help (look at photo)
Semenov [28]

i dont really know but im guessing use ratios. like 4:total volunteers

or something like that

7 0
3 years ago
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