Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C
![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)
LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
Answer:
what is the question? May you please show us
Step-by-step explanation:
Answer:
y = (-1/2)x
Step-by-step explanation:
As we go from (-4, 2) to (6, -3), x (the "run") increases by 10 and y (the "rise") decreases by 5. Thus, the slope of the line connecting these two points is m = rise / run = m = -5/10, or m = -1/2.
We adapt the slope-intercept form as follows: y = mx + b becomes
2 = (-1/2)(-4) + b, or
2 = 2 + b. Therefore, b must be 0. The desired eequation is y = (-1/2)x.
Answer: Calculation:
z = |3+4i|
Result: Rectangular form: z = 5
I hope this will help you!!!!
