Answer:
x = 2±sqrt(11)
Step-by-step explanation:
x^2 -4x - 7 =0
Add 7 to each side
x^2 -4x -7+7 =0+7
x^2 -4x =7
To complete the square take the coefficient of the x term and divide by 2 and then square it. Add it to both sides
-4 /2 = -2 then square
(-2)^2 = 4
Add 4 to both sides
x^2 -4x+4 =7+4
x^2 -4x+4 = 11
Factor the left side into (x-b/2)^2
(x-2)^2 =11
Take the square root of each side
sqrt((x-2)^2) =±sqrt(11)
x-2 = ±sqrt(11)
Add to to each side
x-2+2 = 2±sqrt(11)
x = 2±sqrt(11)
Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
Answer:
10
Step-by-step explanation:
1. 2(4.5)+1
2. 9+1
3. 10
Answer:
−0.608761429
Step-by-step explanation:
use the pathagreom theorem if you have two sides subtract that from 180
