Your answer is A. he can get 19.37 songs because 25 divided by 1.29 is 19.37 (mark me as brainliest, this answer is 100% accurate)
Answer:
t = 9
Step-by-step explanation:
Step 1:
- t = 9 ( t - 10 ) Equation
Step 2:
- t = 9t - 90 Multiply
Step 3:
- t + 90 = 9t Add 90 on both sides
Step 4:
90 = 10t Add t on both sides
Step 5:
t = 90 ÷ 10 Divide
Answer:
t = 9
Hope This Helps :)
So first we need to know the order of operations
P - Parenthesis
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
Then the special cases:
(I have attached a picture below)
Lets get into action!
(5a - 2)(5a + 2) - 3( 1 - a ) - 3a
25a² - 4 - 3 + 3a - 3a
25a² - 7
25a² - 7 is the answer
Answer:
3) C
Step-by-step explanation:
The question is asking which pair is equal. Work through each problem to solve.
8(2r) and 10r
16r ≠ 10r
6r + 3 and 9r
6r + 3 ≠ 9r
9(3r - 4) and 27r - 36
27r - 36 = 27r - 36
r + r + r + r + r and r⁵
5r ≠ r⁵
Answer:
20 m
Step-by-step explanation:
Here, we will take,
The distance from top of the building to the tip of the shadow = Hypotenuse = 37 m
The length of shadow of the building = base = 32 m
let, height of the building = perpendicular = p
According to the Pythagoras Theorem,
(Hypotenuse)² = (Base)² + (Perpendicular)²
<em>h</em><em>²</em><em> </em><em>=</em><em> </em><em>b²</em><em> </em><em>+</em><em> </em><em>p²</em>
<em>p²</em><em> </em><em>=</em><em> </em><em>h²</em><em> </em><em>-</em><em> </em><em>b</em><em>²</em>
<em>p²</em><em> </em><em>=</em><em> </em><em>37</em><em>²</em><em> </em><em>-</em><em> </em><em>32</em><em>²</em><em> </em>
<em>p²</em><em> </em><em>=</em><em> </em><em>1</em><em>3</em><em>6</em><em>9</em><em> </em><em>-</em><em> </em><em>1</em><em>0</em><em>2</em><em>4</em>
<em>p²</em><em> </em><em>=</em><em> </em><em>34</em><em>5</em>
<em>p </em><em>=</em><em> </em><em>1</em><em>8</em><em>.</em><em>5</em><em>7</em>
and if we round the solution to nearest tenth it will be 20.
<u>Hence,</u><u> </u><u>height </u><u>of </u><u>the </u><u>building </u><u>is </u><u>2</u><u>0</u><u> </u><u>m.</u>
