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faltersainse [42]
3 years ago
11

What is the logarithmic form of the equation e3x ≈ 3247?

Mathematics
2 answers:
Elza [17]3 years ago
5 0
<span> log3x3247 = e
</span> ln 3247 = 3x <span> 3 logxe = 3247
</span>
<span> ln 3x = 3247
</span>option B is right 
hope this helps
shusha [124]3 years ago
3 0

Answer:

Option B - ln 3247 = 3x

Step-by-step explanation:

We have given that : Equation =  e^{3x} =3247

To find : The logarithmic form of the given equation

Solution : e^{3x} =3247

Taking 'ln' both side (ln= natural log)

ln(e^{3x}) =ln(3247)  .........(1)

∵ Logarithm rule -   ln(e^x)= x

∴   ln(e^{3x})= 3x

Now we put back in equation (1) we get,

3x =ln(3247)

or ln 3247=3x

Therefore, option B is correct

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29.5+/-1.11

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7 0
2 years ago
If Acot theta + Bcot theta =4 and
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Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

 

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

2

−b  

2

)[∵csc  

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θ−cot  

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θ=1]

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Step-by-step explanation:

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