Hello!
Since you have a board that is 8 and 1/4 feet long, the easy way to calculate how many 1/2 feet are on 8 feet is two multiply 8 x 2, since there are two halves of a foot, in one foot (because two halves equal one whole). Now this may sound confusing but we can double check.
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| | As we can see here, there are two rows, each with 8 halves.
V V So now we multiply 8 x 2 and get 16.
1/2 + 1/2 = 1
1/2 + 1/2 = 1
1/2 + 1/2 = 1
1/2 + 1/2 = 1
1/2 + 1/2 = 1
1/2 + 1/2 = 1
1/2 + 1/2 = 1
1/2 + 1/2 = 1
^-- Now if you add all of these, it's 8, proving that you can do 8 x 2
Yes, you may be asking, "What about the 1/4?" Don't worry about it! Questions like this try to trick you into making it more complicated, it asks how many halves are in 8 and 1/4, but 1/4 isn't enough to make a half so we leave it alone.
Answer:
92 sq. inches
Step-by-step explanation:
Total paper required = total surface area
Surface area of a cuboid = 2[(l×b) + (l×h) + (b×h)],
Where 'l' is the length, 'b' is the breadth and 'h' is the height
For the box, total surface area = 2[(8×3) + (3×2) + (8×2)]
=2[24 + 6 + 16]
=2[46]
= 92 sq. inches
Answer:
y = -8x + 4
Step-by-step explanation:
Using the y = mx +b for the slope intercept form, the m stands for the slope and the b stands for the y-intercept.
In this case, the slope is -8 and the y-int is 4 so we naturally plug those in
You have 4 options:
4 cards: because you draw cards and don't replace them your chance p changes on every trial, so it can't be a binomial experiment
roll 2 dice until...: a binomial experiment must have a consistent amount of trials, by doing an action until some condition is fulfilled violates this as the amount of trials or throws in this case is random
ask 9 people: there are three options, binomial experiments can only have 2
the only option left is the spinner, which is a binomial experiment
Lower extreme- 8
Lower quartile- 20
Median- 30
Upper quartile- 35
Upper extreme- 42
Hope this helps!
