The
first graph.
The equation is x - 1
3
In order to solve it, you need to get x by itself.
Add 1 to both sides. 3+1=4
x
4
Since this is your sign
the arrow has to point towards the left, and the circle needs to be colored in.
Answer:
The domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.
Step-by-step explanation:
We are given that Carly is traveling to visit family.
She drive distance on first day = x
She drive distance on second day = y
We are also given that Carly is travelling a total of 800 miles.
So,x+y=800
We are supposed to find domain and range of this relationship.
y=800-x
Domain : (-∞,∞)
Range:(-∞,∞)
Hence the domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.
Answer:
B. Function 2
Step-by-step explanation:
Line P gradient is
Gradient = rise/run
= 1/4
Negative slope so gradient is - 1/4
Out of all the gradient, the lowest value has to be function 2 or line p & not 1/4r-5 because when r is 1 we get a gradient of 1.
-1/4xr - 5
-1/4x1 - 5
-1/4-5
-1/-1 = 1
Plus, 1 is greater than - 1/4 or - 0.25.
Answer:
C) triangular prism
Step-by-step explanation:
The net represents a three-dimensional shape. The figure that the net represents is a rectangular prism.
Answer:
- (-16x² +10x -3) +(4x² -29x -2)
- (2x² -11x -9) -(14x² +8x -4)
- 2(x -1) -3(4x² +7x +1)
Step-by-step explanation:
I find it takes less work if I can eliminate obviously wrong answers. Toward that end, we can consider the constant terms only:
- -3 +(-2) = -5 . . . . possible equivalent
- -10 -5 = -15 . . . . NOT equivalent
- 3(-5) -2(5) = -25 . . . . NOT equivalent
- -9 -(-4) = -5 . . . . possible equivalent
- -7 -(-5) = -2 . . . . NOT equivalent
- 2(-1) -3(1) = -5 . . possible equivalent
Now, we can go back and check the other terms in the candidate expressions we have identified.
1. (-16x² +10x -3) +(4x² -29x -2) = (-16+4)x² +(10-29)x -5 = -12x² -19x -5 . . . OK
4. (2x² -11x -9) -(14x² +8x -4) = (2-14)x² +(-11-8)x -5 = -12x² -19x -5 . . . OK
6. 2(x -1) -3(4x² +7x +1) = -12x² +(2 -3·7)x -5 = -12x² -19x -5 . . . OK
All three of the "possible equivalent" expressions we identified on the first pass are fully equivalent to the target expression. These are your answer choices.
