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nekit [7.7K]
4 years ago
10

a gym charges a one time fee of $50 and monthly membership charge of $25 the total cost c of being a member of the gym is given

by c (t)=50+25t,where c is the total cost you pay after being a member for t months

Mathematics
2 answers:
anygoal [31]4 years ago
7 0
C(t) = 50 + 25t 
A) So $50 was a one time pay and that's your initial value and each month they need to pay $25. So the slope is 50 
B) the y-int of your problem is $50  



marissa [1.9K]4 years ago
4 0
A. The slope is 25 and it is the rate of change per month. You will pay this additional amount if you go to the gym every month.
b. The y-intercept is 50. This amount is the constant and does not change since it is a one time fee for the year.
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O.9c + 1.89r = 17.01 c=18.9 - 2.1r equation answer
ikadub [295]

Answer:

c=18.90-2.1r

Step-by-step explanation:

<u><em>The complete question is</em></u>

A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per  pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this  situation.

Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.

Then, explain when it might be helpful to write the equation in these forms.

a. c=18.9-2.1r. b. r= -10÷2c+9​

we have that

The linear equation in standard form is

0.90c+1.89r=17.01

where

c is the pounds of chicken

r is the pounds of ribs

step 1

Solve the equation for c

That means ----> isolate the variable c

Subtract 1.89r both sides

0.90c=17.01-1.89r

Divide by 0.90 both sides

c=(17.01-1.89r)/0.90

Simplify

c=18.90-2.1r

step 2

Solve the equation for r

That means ----> isolate the variable r

Subtract 0.90c both sides

1.89r=17.01-0.90c

Divide by 1.89 both sides

r=(17.01-0.90c)/1.89

Simplify

r=9-0.48c

therefore

The equation c=18.90-2.1r is equivalent

The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.

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