Answer:
The Correct and final Answer Is
D) Or option 4
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Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Answer:
21
Step-by-step explanation:
21-12=9
Answer:
my answer was 7.5
Step-by-step explanation:
2
2b+3b-10
4b+3b-10
10-7b=3b fraction bar means divide so...
3b
__ 2
4b because... b-2b=4b and 8-4b=4b
3/4 =7.5 because 4 cant go into three so you add a decimal and a zero and move decimal up and 4 can go into 30 7 time which equals 28 and 30-28 is 2 add another zero and its 20 and 4 goes in 5 times which equals 20 and 20-20=0 so its 7.5 (i hope this helps ;)
Answer:
2 gigabytes of data
Step-by-step explanation:
Given
Amount Jason keeps per month = $68.90
Cost of flat per month = $60.50
Balance for data = 68.90-60.50
Balance for data = $8.40
If 1Gigabyte = $4
x = $8.40
Cross multiply
4x = 8.40
x = 8.40/2
x = 2.20
Hence Jason can only use 2 gigabytes of data while staying within his budget
