Answera. use site specific recombination to incorporate their genome into the host genome for prophage replication until the host's growth is threatened.
Explanation:
A temperate phage is a bacteriophage which incorporate it's genome inside the host organism. It replicates it's own genome within the host cell. It basically uses the site specific recombination so as to incorporate the genome within the host cell.
Answer:
3/16
Explanation:
Given,
Black coat color is dominant over brown coat color.
Long mane is dominant over short mane.
BBLL X bbll =
F1: BbLl = Entire progeny has black color and long mane
BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,
BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1
3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.
Answer: they are all correct so select all
Explanation:
bc i did it and bc i said so
the lithosphere is inbetween
