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avanturin [10]
3 years ago
11

" alt="(\sqrt{} 5xy^{2})x^{4}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
6 0

Answer:

y/5xx^4

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Tips

- the 4 is an exponent

- the dash  is the big check thing

Your welcome

<em><u>my instagram is = itsstephbored</u></em>

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pentagon [3]

Answer:

= x 3048

Step-by-step explanation:

6 0
2 years ago
Hey... Got away from computer hackers yaya :)
kirill115 [55]

Answer

that really good

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4 0
3 years ago
Will mark as brainliest
lapo4ka [179]

Answer:

-1 + 2 = 1

1 + (-2) = -1

-1 - 2 = -3

1 - (-2) = 3

Step-by-step explanation

When you subtract use keep change change

Rule 1 when you add : If the signs are the same add the numbers and take the sign of the bigger number.

Rule 2 when you add : If the signs are different subtract the numbers and take the sign of the bigger number.

I wanted to help you understand and i hope i did that!

8 0
3 years ago
Câu 99: Cho hàm số f x  xác định trên ℝ , bảng biến thiên của hàm số f x   như sau.
OLga [1]

Answer:

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4 0
3 years ago
A^-1/[a^-1 - b^-1] + a^-1/[a^-1 + b^-1]
o-na [289]

\dfrac{a^{-1}}{a^{-1}-b^{-1}}+\dfrac{a^{-1}}{a^{-1}+b^{-1}}=a^{-1}\left(\dfrac{a^{-1}+b^{-1}}{(a^{-1}-b^{-1})(a^{-1}+b^{-1})}+\dfrac{a^{-1}-b^{-1}}{(a^{-1}+b^{-1})(a^{-1}-b^{-1})}\right)

=a^{-1}\left(\dfrac{(a^{-1}+b^{-1})+(a^{-1}-b^{-1})}{a^{-2}-b^{-2}}\right)

=\dfrac{2a^{-2}}{a^{-2}-b^{-2}}

=\dfrac{2b^2}{b^2-a^2}

5 0
3 years ago
Read 2 more answers
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