Answer:
Area = 32 square inches
Step-by-step explanation:
It is given that ,
1). an isosceles right triangle with a perimeter of 27 inches
Then the base and height are equal
2). the longest side measures 11 inches
<u>To find the smaller side</u>
Then sum of other 2 sides = 27 - 11 = 16
Base = height = 16/2 = 8 inches
<u>To find the are of triangle</u>
Area = 1/2 * Base*Height
Base = 8 inches and Height = 8 inches
Area = 1/2 * 8* 8 = 32 square inches

Finding the extreme point :

Now,
f''( x ) at x = 1/3 and -1 is :

Therefore, it is maximum at x = -1 and minimum at x = 1/3 .
Hence, this is the required solution.
Divide each by 2
40= 20
144= 72
Divide by 2 again
20=10
72=36
Divide by 2 one more time
10=5
36=18
Ans= 5:18
Length = ((8^2)-(5^2))^(1/2) = (64-25)^0.5 = 39^0.5
Therefor width = 5(39^0.5)
Approx = 31.22
Answer:
To be honest I think its D
Step-by-step explanation: