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Diano4ka-milaya [45]
3 years ago
11

A^-1/[a^-1 - b^-1] + a^-1/[a^-1 + b^-1]

Mathematics
2 answers:
o-na [289]3 years ago
5 0

\dfrac{a^{-1}}{a^{-1}-b^{-1}}+\dfrac{a^{-1}}{a^{-1}+b^{-1}}=a^{-1}\left(\dfrac{a^{-1}+b^{-1}}{(a^{-1}-b^{-1})(a^{-1}+b^{-1})}+\dfrac{a^{-1}-b^{-1}}{(a^{-1}+b^{-1})(a^{-1}-b^{-1})}\right)

=a^{-1}\left(\dfrac{(a^{-1}+b^{-1})+(a^{-1}-b^{-1})}{a^{-2}-b^{-2}}\right)

=\dfrac{2a^{-2}}{a^{-2}-b^{-2}}

=\dfrac{2b^2}{b^2-a^2}

Lena [83]3 years ago
3 0

Answer: Hopes it helps..... Your welcome

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Answer:

y=35

Step-by-step explanation:

y in (-oo:+oo)

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14-((2*y)/5) = 0

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Given that,
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The question given is incomplete, a proper question could be
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