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ValentinkaMS [17]
3 years ago
6

i have two questions. Is y= (4 2/3) x proportonal? and is y= 3(x - 1) proportional? If it’s proportional, what’s the constant va

riable?
Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y = 4\frac{2}{3}x\qquad \qquad yes\qquad \checkmark\qquad \qquad k = 4\frac{2}{3} \\\\[-0.35em] ~\dotfill\\\\ y=3(x-1)\implies \stackrel{\textit{distributing}}{y=3x-3}\qquad \qquad yes\qquad \checkmark \qquad \qquad k=3

bear in mind that, direct proportional equations have a y-intercept.

for y = kx, is pretty much y = kx + 0, where 0 = y-intercept.

and the "k" constant of proportionality, is pretty much just its slope.

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Hector is flying a kite. He has let out 86 feet
Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is 42.258333^{0} ≅ 42.26^{0}

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = \frac{opposite}{hypotenus}

Sin 42.26^{0} = \frac{x}{86}

⇒ x = 86 x Sin 42.26^{0}

      = 86 x 0.6725

     = 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

                                    = 57.84 + 4

                                   = 61.84 feet

7 0
3 years ago
Equation of the line that is perpendicular to y= 1/8x -2 and goes through the point <br> (-2,-3)
larisa [96]
The answer to this equation is y=-8x-19



I hope this helps!!!!!!!!
7 0
3 years ago
Read 2 more answers
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
3 years ago
1. Describe the relationship between the terms in the sequence 13, 26, 52,
Vilka [71]

Answer: All of the numbers in the sequence are going up twice the amount as before. The next three terms will be 208, 416, 832

4 0
2 years ago
Read 2 more answers
Simplify 5y^-2<br><br> please help fast!!!
Semmy [17]

Answer:

25y2 i think

Step-by-step explanation:

i hope it helps

4 0
2 years ago
Read 2 more answers
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