<span>Factors are the numbers you multiply together
to get another number:</span>
There can be many factors of a number.
<span>Example: All the factors of 12</span><span>2 × 6 = 12, but also 3 × 4 = 12, and of course 1 × 12 = 12. </span>
So 1, 2, 3, 4, 6 and 12 are factors of 12.
And also -1,-2,-3,-4,-6 and -12, because you get a positive number when you multiply two negatives, such as (-2)×(-6) = 12
Answer: 1, 2, 3, 4, 6, 12, -1, -2, -3, -4, -6, -12
Answer:
3 and 9
if f(x)=x^2+13 and g(x)=12x-14
Step-by-step explanation:
So when we are looking for the intersection of two functions, we are trying to figure out when they are the same. When you think same, you should think equal (=).
So we want to find when f(x)=g(x) for x.
f(x)=g(x)
![x^2+13=12x-14](https://tex.z-dn.net/?f=x%5E2%2B13%3D12x-14)
Let's get everything to one side.
Subtracting 12x and adding 14 to both sides.
![x^2+13+14-12x=0](https://tex.z-dn.net/?f=x%5E2%2B13%2B14-12x%3D0)
I'm going to reorder the left hand side and also simplify the 13+14 part:
![x^2-12x+27=0](https://tex.z-dn.net/?f=x%5E2-12x%2B27%3D0)
Now since the coefficent of x^2 is just 1 our job is to find two numbers that multiply to be 27 and add up to be -12.
Those numbers are -3 and -9 since -3(-9)=27 and -3+(-9)=-12.
So the factored form of our equation is
![(x-3)(x-9)=0](https://tex.z-dn.net/?f=%28x-3%29%28x-9%29%3D0)
Since the product is 0, then at least one of the factors must be 0.
So we want to solve both x-3=0 and x-9=0.
x-3=0 can be solved by adding 3 on both sides. This gives us x=3.
x-9=9 can be solved by adding 9 on both sides. This gives us x=9.
The intersection of f and g happens at x=3 or x=9.
The very first one (the very left one)
Answer:
SA = 664 in.²
Step-by-step explanation:
Surface area of the rectangular prism = 2(LW + LH + WH)
Where,
Length (L) = 16 in.
Width (W) = 5 in.
Height (H) = 12 in.
Substitute the values
Surface area of the rectangular prism = 2(16*5 + 16*12 + 5*12)
= 2(80 + 192 + 60)
= 2(332)
= 664 in.²
Answer:
15 x 10^-1
Step-by-step explanation:
36÷24=1.5
In this case I'm considering 15 as the base of my standard form.
To make 15 a 1.5, you'll have to move from right to left one unit and on the number line moving from the right to left gives you a negative number of units moved