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Ket [755]
3 years ago
8

What is the probability of two dice being rolled and it being less than 7 and divisible by 3

Mathematics
2 answers:
Luden [163]3 years ago
8 0

Answer:

Step-by-step explanation:

(1, 1) <u>(1, 2)</u> (1, 3) (1, 4) <u>(1, 5)</u> (1, 6)

<u>(2, 1)</u> (2, 2) (2, 3)<u> (2, 4)</u> (2, 5) (2, 6)

(3, 1) (3, 2) <u>(3, 3)</u><u> </u>(3, 4) (3, 5) <u>(3, 6) </u>

(4, 1) <u>(4, 2</u>) (4, 3) (4, 4)<u> (4, 5) </u>(4, 6)

<u>(5, 1)</u> (5, 2) (5, 3) <u>(5, 4)</u> (5, 5) (5, 6)

(6, 1) (6, 2) <u>(6, 3) </u>(6, 4) (6, 5) <u>(6, 6) </u>

The bold numbers are less than 7, and the <u>underlined numbers</u> are <u>divisible by 3</u>. The total number of numbers are 36.

The number of numbers that are <u>both</u> <u>underlined</u> and bold are 7.

The probability is 7/36.

Ivenika [448]3 years ago
4 0

Answer:

2/12 (1/6)

Step-by-step explanation:

Two dice both have 6 numbers. So thats 12 numbers in total.

1-6 are less than seven and only 2 of those numbers are divisible by 3. (3 & 6)

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