Question

What is the probability of two dice being rolled and it being less than 7 and divisible by 3

Answer 1

Answer:

Step-by-step explanation:

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The bold numbers are less than 7, and the underlined numbers are divisible by 3. The total number of numbers are 36.

The number of numbers that are both underlined and bold are 7.

The probability is 7/36.

Answer 2

Answer:

2/12 (1/6)

Step-by-step explanation:

Two dice both have 6 numbers. So thats 12 numbers in total.

1-6 are less than seven and only 2 of those numbers are divisible by 3. (3 & 6)