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tiny-mole [99]
4 years ago
5

What is the missing constant term in the perfect square that starts with x^2+6xx 2 +6xx, start superscript, 2, end superscript,

plus, 6, x ?
Mathematics
1 answer:
stira [4]4 years ago
7 0
For this case we have the following polynomial:
 x ^ 2 + 6x
 The missing value to complete the square is given by:
 x ^ 2 + 6x + (6/2) ^ 2
 Rewriting we have:
 x ^ 2 + 6x + (3) ^ 2
 x ^ 2 + 6x + 9
 Then, completing the square we have:
 (x + 3) ^ 2
 Answer:
 the missing constant term in the perfect square is:
 9
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When four fifths 4 5 of a number is subtracted from 1414​, the result is 22. find the number?
galben [10]
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8 0
3 years ago
What is a perfect square? Why is <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%208x%20%2B16" id="TexFormula1" title="x^{2}
ivanzaharov [21]

Answer:

It is a perfect square. Explanation below.

Explanation:

Perfect squares are of the form

(

a

+

b

)

2

=

a

2

+

2

a

b

+

b

2

. In polynomials of x, the a-term is always x.(

(

x

+

c

)

2

=

x

2

+

2

c

x

+

c

2

)

x

2

+

8

x

+

16

is the given trinomial. Notice that the first term and the constant are both perfect squares:

x

2

is the square of x and 16 is the square of 4.

So we find that the first and last terms correspond to our expansion. Now we must check if the middle term,

8

x

is of the form

2

c

x

.

The middle term is twice the constant times x, so it is

2

×

4

×

x

=

8

x

.

Okay, we found out that the trinomial is of the form

(

x

+

c

)

2

, where

x

=

x

and

c

=

4

.

Let us rewrite it as

x

2

+

8

x

+

16

=

(

x

+

4

)

2

. Now we can say it is a perfect square, as it is the square of

(

x

+

4

)

.

3 0
3 years ago
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