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4 years ago

if 3 the complement of 7,98 is the complement of 2 ,and 845 is the complement of 155, what is the complement of 43 ?

Mathematics

1 answer:

krok68 [10]4 years ago

6 0

Answer:

9,957

Step-by-step explanation:

10=7+3

100=2+98

1,000=155+845

10,000=43+x

x= 10,000-43

x=9957..

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2 points

miskamm [114]

The x - intercept of 5x - 3y = 15 is (3, 0)

The y -intercept of 5x - 3y = 15 is (0, -5)

<h3>Solution:</h3>

Given equation is 5x - 3y = 15

To find: x - intercept and y -intercept

The x intercept is the point where the line crosses the x axis. At this point y = 0

The y intercept is the point where the line crosses the y axis. At this point x = 0.

Finding x - intercept:

To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x

So put y = 0 in given equation

5x - 3(0) = 15

5x = 15

x = 3

So the x - intercept is (3, 0)

Finding y - intercept:

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y

So put x = 0 in given equation

5(0) - 3y = 15

-3y = 15

y = -5

So the y - intercept is (0, -5)

5 0

3 years ago

What is the product? 3a(8a – 6b)

ANTONII [103]

I believe it would be 24a^2-18ab.

8 0

3 years ago

Read 2 more answers

Find length indicated

VMariaS [17]

Answer:

Step-by-step explanation:

the equation is

33 = 3x-28+3x-30+x

33=7x-28-30

33=7x-58

+58 +58

91=7x

x=13

DE=13

3 0

3 years ago

HELP HELP HELP HELP HELP PELADE PLEASE PLEASE IM DESPERATE SNSMXMDMAK

Vera_Pavlovna [14]

Answer:

see below

Step-by-step explanation:

The points at the corners of the given figure are ...

(0, 0), (0, 4), (3, 4), (3, 0)

When the figure is scaled by a factor of 1/3, each of the coordinates is multiplied by 1/3:

(0, 0), (0, 4/3), (1, 4/3), (1, 0) . . . . . points scaled by 1/3

When the figure is scaled by a factor of 3/2, each of the coordinates is multiplied by 3/2:

(0, 0), (0, 6), (9/2, 6), (9/2, 0) . . . . . . points scaled by 3/2

The points that are on your list are shown in bold above.

6 0

4 years ago

Persons A and B are at the beach, their eyes are 5 ft and 6 ft, respectively, above sea level. How many miles farther out is Per

Marysya12 [62]

Answer:

The radius of the earth is something like 4000 miles= about 20,000,000 feet. (Look up the exact radius of the earth to calculate the correct number yourself, I'm too lazy!)

The horizon is where you're looking at a tangent to the earth's surface. Since the tangent to a circle is perpendicular to the radius (if we assume the earth is a perfect sphere), we can set up a right angled triangle:

H...P

Where C is the centre of the earth, H is the horizon, and P is the person. CH = 20,000,000 feet. CP = 20,000,005 feet (in the case of the 5' person, that'd be me :) And there is a right angle at H.

So using Pythagoras' theorem, if d = PH, then:

d^2 = 20,000,005^2 - 20,000,000^2

=> d^2 = 200,000,025

=> d = 14142 feet (just under 3 miles)

For a 6' person:

d^2 = 20,000,006^2 - 20,000,000^2

=> d^2 = 240,000,036

=> d = 15491 feet

So the difference is 1349 feet or 0.256 miles

Repeat this exercise with the real radius of the earth (in feet) to get the correct answer, but it'll be pretty close to what I've given here

4 0

3 years ago

if 3 the complement of 7,98 is the complement of 2 ,and 845 is the complement of 155, what is the complement of 43 ?​

if 3 the complement of 7,98 is the complement of 2 ,and 845 is the complement of 155, what is the complement of 43 ?