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Arisa [49]
3 years ago
12

How many protons and electrons does an ion of Ca2+ have?

Chemistry
1 answer:
murzikaleks [220]3 years ago
8 0
The neutral atom also has 20 electrons, but to form the 2+ ion, it needs to lose 2 of these, giving just 18 electrons. A neutral calcium atom has 20 protons and so 20 electrons. A calcium ion has a 2+ charge so it has lost 2 electrons. It has 20 protons and 18 neutrons.
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QUESTION 4
Nikolay [14]

Answer:

False

Explanation:

According to kinetic molecular theory, all collisions are perfectly elastic and energy is conserved.

3 0
3 years ago
What is the approximate percent by mass of oxygen in C2H4O2
kherson [118]

Answer:

Approximately 53.3  %.

Explanation:

Molar mass of C2H4O2

= 2 * 12.011 + 4 * 1.008 + 2 * 15.999

=  60.052

% oxygen = (31.998* 100) / 60.052 = 53.28 %

6 0
3 years ago
What did the Great Compromise and the Three-Fifths Compromise decide?
MissTica

Answer:

The Great Compromise settled matters of representation in the federal government. The Three-Fifths Compromise settled matters of representation when it came to the enslaved population of southern states and the importation of enslaved Africans.

Explanation:

7 0
3 years ago
22)
Setler79 [48]

Answer: A) 4.2 x 10^20

Explanation:

All of the answers are pretty much the same so it comes down to significant digits.

You always go with the <u>least number of significant digits</u> that you have been given.

So 0.24g only has 2 so our answer will only have 2 significant digits.

If you want to know how to do the math here it is:

Avogadro's Number: 6.022 x 10^23

This number also equals 1 mole.

1 mole of sucrose is equal to 342.3g.

So the equation is set up like this:

0.24g x 1 mol / 342.3 g x 6.022 x 10^23 / 1 mol = 4.2 x 10^20 molecules.

6 0
4 years ago
How many moles is 4X1023 atoms Ne?​
Mashcka [7]

Answer:

<h2>0.66 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

n =  \frac{4 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{4}{6.02}  \\  = 0.664451...

We have the final answer as

<h3>0.66 moles</h3>

Hope this helps you

6 0
3 years ago
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