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zaharov [31]
3 years ago
14

Mason has 29.8 ounces of peanuts. He eats 5 ounces of the peanuts. Then he divides the rest of the peanuts equally among 4 frien

ds.
How many ounces of peanuts does each friend get?

Enter your answer as a decimal in the box.
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0

Alright, so the first step we are gonna do to solve this problem is subtract since Mason ate 5 ounces of the peanuts and so, we need to subtract 5 out of 29.8.

29.8 - 5 = 24.8

So, now there is 24.8 ounces.

Now we move onto the next step which is division. As you can see in the question it says "Then he divides the rest of the peanuts equally among 4 friends."

24. 8 ÷ 4 = 6.2

Since the answer is supposed to be a decimal..that's your answer!

So overall, each of Mason's friends get 6.2 ounces of peanuts.

Hope this helps!

If you are needing any more help, comment below this comment for any contact of mine. I'll be glad to help!

- Kana

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artcher [175]

Answer:

x =53.85

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Let x be the original price

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x * 78% = 42

Change to decimal form.

78x = 42

Divide each side by .78.

78x/.78 = 42/.78

Rounding to the nearest cent

x =53.85

4 0
2 years ago
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8 0
3 years ago
I need a little extra help with number three
diamong [38]

Answer:

The answer to your question is:

Step-by-step explanation:

Data

f(x) = -2x² + 8x - 2

Process

                -2x² + 8x = y + 2

                -2(x² - 4x + 4) = y + 2 - 8

                -2(x - 2)² = y - 6

                    (x - 2)² = 1/2 (y - 6)

Vertex = (2, 6)

Axis of symmetry =   x = 2

y-intercept

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Domain    (-∞, ∞)

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See the graph below

6 0
3 years ago
GCF And LCM of 24, 36, 45
faltersainse [42]

Answer:

Step-by-step explanation:

First lets prime factorize each number

24 = 2 x 2 x 2 x 3

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45 = 3 x 3 x 5

GCF = 3    (3 is the only common prime number factor in the 3 numbers)

LCM = 2 x 2 x 2 x 3 x 3 x 5

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Happy to help :)

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Considering the graph of the velocity of the car, it is found that the interval in which it was stopped at a traffic light was:

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<h3>When is a car stopped at a traffic light?</h3>

When a car is stopped at a traffic light, the car is not moving, that is, it's velocity is of zero.

In this problem, the graph gives the <u>velocity as a function of time</u>, and it is at zero between 3 and 4 minutes, hence the interval in which it was stopped at a traffic light was:

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