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sergeinik [125]
3 years ago
10

What is the area of a rectangle with vertices at (7,3), (12,3), (12, 11), and (7,

Mathematics
2 answers:
NISA [10]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Setler [38]3 years ago
6 0

Answer: 40 units

Step-by-step explanation:

(7,3) (12,3) on the same y coordinate, 5 squares apart

(12,3) (12,11) on the same x coordinate, 8 squares apart

8 × 5 = 40

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d  = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

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X (dy/dx) = (y-1/y+1)-y
notsponge [240]
F'( \frac{y-1}{y+1})-y=
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2

2×10=200-17=183

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3 years ago
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