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Lesechka [4]
3 years ago
14

Which one is bigger 64 in or 5 ft

Mathematics
2 answers:
anzhelika [568]3 years ago
5 0
64 inches is greater than 5ft. There are 12 inches in a foot. You should divide 64 by 12. You will get 5.333 (repeating, in this instance we will round up to 5.4)
Inessa [10]3 years ago
4 0

64 inches

Step-by-step explanation:

12 inches equals 1 foot so

12*5=60 inches which means it will be bigger than 5 feet.

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Convert the mixed number to an improper fraction. 2 7/10 A.14/10 B.27/10 C.34/10 D.37/10
boyakko [2]
So, to make a mixed number into an improper fraction, you have to multiply the whole number by the denominator and then add the numerator o that number.
2 and 7/10:
2x10=20+7=27/10!
<u>The answer would be B!</u>
I hope this helps!
7 0
3 years ago
Read 2 more answers
I need help please....
Zina [86]

Answer:

1/10

Step-by-step explanation:

5 0
3 years ago
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(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!
Anastaziya [24]

Answer:

5x^2+7x+30+\frac{102}{x-3}

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

6 0
2 years ago
Read 2 more answers
Please help me. 5(m-7)=-8(3m+8)
inessss [21]

Answer:

m = -1

Step-by-step explanation:

Solve for m:

5 (m - 7) = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the left hand side:

5 m - 35 = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

5 m - 35 = -24 m - 64

Hint: | Move terms with m to the left hand side.

Add 24 m to both sides:

24 m + 5 m - 35 = (24 m - 24 m) - 64

Hint: | Look for the difference of two identical terms.

24 m - 24 m = 0:

24 m + 5 m - 35 = -64

Hint: | Group like terms in 24 m + 5 m - 35.

Grouping like terms, 24 m + 5 m - 35 = (5 m + 24 m) - 35:

(5 m + 24 m) - 35 = -64

Hint: | Add like terms in 5 m + 24 m.

5 m + 24 m = 29 m:

29 m - 35 = -64

Hint: | Isolate terms with m to the left hand side.

Add 35 to both sides:

29 m + (35 - 35) = 35 - 64

Hint: | Look for the difference of two identical terms.

35 - 35 = 0:

29 m = 35 - 64

Hint: | Evaluate 35 - 64.

35 - 64 = -29:

29 m = -29

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 29 m = -29 by 29:

(29 m)/29 = (-29)/29

Hint: | Any nonzero number divided by itself is one.

29/29 = 1:

m = (-29)/29

Hint: | Reduce (-29)/29 to lowest terms. Start by finding the GCD of -29 and 29.

The gcd of -29 and 29 is 29, so (-29)/29 = (29 (-1))/(29×1) = 29/29×-1 = -1:

Answer: m = -1

7 0
3 years ago
How many solutions does this equation have? 6x+5=4x+5
Travka [436]

:\implies \sf  6x +5 = 4x +5

: \implies \sf  6x +5 -4x = 5

:\implies \sf  2x = 5-5

:\implies \sf  2x = 0

:\implies \sf  x = 0

Seems like "6x+5=4x+5" has only one solution that's 0.

3 0
2 years ago
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