I know that the relationship between altitude and atmospheric density is that the higher the altitude, the lesser the density, and the lower the altitude the higher the density. Lower density float to the top, and higher density is 'heavy' so it comes down
Answer:
Check the explanation
Explanation:
To solve the problem, we need to analyze all forces acting on a bicycle individually. In question, student bikes on flat terrain so gravity force doesn't affect the road load. This is the case of uniform acceleration and deceleration so need to calculate average velocity to find Air resistance.
Kindly check the attached images below to see the step by step explanation to the question above.
El peso anywhere = (mass) x (gravity there). Gravity en la Tierra = 9.81 m/s^2. Gravity en la Luna = 1.62 m/s^2.
The image is always virtual and erect. The image is highly diminished or point sized. It is always formed between F and P.
Answer:
a) v = 13.8 m / s
, b) a = 95.49 m / s²
, c) a force that goes to the center of the carnival ride and d) μ = 0.10
Explanation:
For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics
a) reduce the magnitudes to the SI system
w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s
The equation that relates linear and angular velocity is
v = w r
v = 6.91 2
v = 13.8 m / s
b) centripetal acceleration is given by
a = v² / r = w² r
a = 6.91² 2
a = 95.49 m / s²
c) this acceleration is produced by a force that goes to the center of the carnival ride
d) Here we use Newton's second law
fr -W = 0
fr = W
μ N = mg
Radial shaft
N = m a
N = m w² r
μ m w² r = m g
μ = g / w² r
μ = 9.8 / 6.91² 2
μ = 0.10
