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myrzilka [38]
3 years ago
13

A box experiences a force of 2 N to the left and 3 N to the right. Which is true of the box's motion?

Physics
2 answers:
Nostrana [21]3 years ago
5 0
Below are the choices:

<span> A) The box will slow down.
B) The box's velocity will be 1 m/s.
C) The box's velocity will not change.
 D) The box will experience acceleration 
</span>
The answer is D) The box will experience acceleration 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
jok3333 [9.3K]3 years ago
4 0

Answer:

The motion of box is accelerated and the direction of acceleration is rightwards.

Explanation:

F1 = 2 n left

F2 = 3 N right

The net force acting on the box = F = F2 - F1 = 3 - 2 = 1 N right

As there is a net force acting on the box, so there is an acceleration in the box. If there is an acceleration, the box is in motion under the constant acceleration, it means the velocity of box is increasing.

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A point charge is released from rest in a region containing an electric field. The charge will start to move
kotykmax [81]

Answer:

b) in a direction that makes its potential energy decrease.

Explanation:

  • As the electric field has the direction that would take a positive test charge under its sole influence, the positive test charge, will have an increase in its kinetic energy.
  • Due to the conservation of energy, in absence of non-conservative forces, this increment must be equal and opposite  to the  change in electric potential energy, which will be always negative, independent of the sign of the charge.

6 0
3 years ago
the particles that make up a rock are constantly in motion however a rock does not visibly vibrate. why do you think this?
Ivahew [28]

I think this is because the particles don't know or care about each other,
and they act completely without any peer pressure.  The direction in which
any one particle vibrates is completely random, and there is no connection
or influence among the particles. That means that any direction is just as likely
as any other direction for the next vibration, and they all wind up vibrating in
different directions.  There is a tiny tiny tiny tiny chance that all of them could
vibrate in the same direction for just an instant; if that ever happened, the rock
would suddenly jump up in the air.  That's actually true, but the chance is so tiny
that it hasn't ever happened yet.  In fact, the chance is so tiny, that when scientists
do their calculations of particle vibrations, they assume that the chance is zero,
and that makes the calculations simpler.

3 0
3 years ago
I need the answer for Earths mass and the mass and weight for Mars.
Savatey [412]
.9736 x 1024 kg. That’s a big number, so let’s write it out in full: 5,973,600,000,000,000,000,000,000 kg. You could also say the Earth’s mass is 5.9 sextillion tonnes and the mass of Mars is 7.08 x 1020 tons or 6.42 X 1020 metric tons
8 0
3 years ago
The maximum displacement in an oscillatory motion is A = 0.49 m. Determine the position x at which the kinetic energy of the par
amid [387]

Answer:

x = 0.40 m

Explanation:

  • When the displacement is maximum, the particle is momentarily at rest, which means that at this point (assuming no friction present) all the mechanical energy is elastic potential, which can be written as follows:

      E_{tot} = U_{o} = \frac{1}{2} *k*A^{2}  (1)

  • Since in absence of friction, total mechanical energy must keep constant, this means that at any time, the sum of the kinetic and potential energy, must be equal to (1), as follows:

       E_{tot} = U_{o} = \frac{1}{2} *k*A^{2}  = (KE)_{f} + U_{f}  (2)

  • If KEf = U/2f, replacing in (2), we get:

      E_{tot} = U_{o} = \frac{1}{2} *k*A^{2}  = (U/2)_{f} + U_{f} =  \frac{3}{2} *U_{f}  (3)

  • At any point, the elastic potential energy is given by the following expression:

       U_{f} = \frac{1}{2} *k*x^{2}   (4)

      where k= spring constant (N/m) and x is the displacement from the

      equilibrium position.

  • Replacing (4) in (3), simplifying and rearranging, we get:

       E_{tot} = U_{o} = \frac{1}{2} *A^{2}  =  \frac{3}{4} *x^{2}   (5)

  • Finally, solving for x, we get:

        x = \sqrt{\frac{2}{3} } * A =  \sqrt{\frac{2}{3} } * 0.49m = 0.40 m  (6)

8 0
3 years ago
Just think about this.
diamong [38]
This ain’t the place, bud. If you have a QUESTION, then you can post it here.
8 0
3 years ago
Read 2 more answers
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