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Advocard [28]
3 years ago
6

The density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas

ured from the planet's surface). What type of relationship exists between the altitude and the atmospheric density, and what would the atmospheric density be at an altitude of 1,291 kilometers?

Physics
1 answer:
mixer [17]3 years ago
6 0
I know that the relationship between altitude and atmospheric density is that the higher the altitude, the lesser the density, and the lower the altitude the higher the density. Lower density float to the top, and higher density is 'heavy' so it comes down
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"A student bikes to school by traveling first dN = 0.900" and "Similarly, let d⃗ W be the displacement vector corresponding to t
raketka [301]

Complete Question

A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.

Express your answer as two numbers separated by a comma. Be careful with your signs.

Answer:

The value is  dT  =  ( -0.3,  0.8)

Explanation:

From the question we are told that

   The first displacement is  dN  =  0.900 \  due  \  North i.e positive  y-axis

   The  second displacement is  dW =  0.300 \  miles  \  due \  west i.e negative  x-axis

   The final displacement is  dS =  0.100 \  miles \ due \ south i.e  negative  y-axis

Generally dW in component for is  

      dW =  (-0.3 ,  0)  

Generally the  total displacement of the student is mathematically represented as

     dT  =  ( -0.3,  (0.90 - 0.10))

      dT  =  ( -0.3,  0.8)

 

   

   

6 0
3 years ago
What percent of earth's density does Jupiter have?
Ivan
Density of Earth: 5.514 g/cm³
Density of Jupiter: <span>1.326 g/cm³

1.326 g/cm³ / 5.514 g/cm³ </span>≈ <span>0,24
0,24 * 100 = 24%

Jupiter has 24% of earth's density.

(Density numbers are from internet, you may calculate with your own ones if u have )</span>
3 0
4 years ago
If you added 5 x more mass into a wheelbarrow, how much greater would
aev [14]

Answer:

5 x biger

Explanation:

becuze if it ia 5× more it nids 5×more force to be =

7 0
3 years ago
A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the
Shkiper50 [21]

Answer:

 ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round  = 144 Kg

angle =  33.2°

moment of inertia

I = \dfrac{1}{2} m R^2

I = \dfrac{1}{2}\times 144 \times 2.75^2

    I = 544.5 kg.m²

torque = force  x radius

τ = 37.7 x  2.75

τ = 103.675 N.m

angular acceleration

\alpha= \dfrac{\tau}{I}

\alpha= \dfrac{103.675}{544.5}

 α = 0.190 rad/s²

now ,

distance = 33.2\times \dfrca{2\pi}{360}

d = 0.579 rad

we know,

using equation of rotational motion

d = \omega t + \dfrac{1}{2}\alpha t^2

0.579 = \dfrac{1}{2}\times 0.190\times t^2

 t = 2.46 s

angular speed

 ω =  α  x t

 ω = 0.19 x 2.46

 ω = 0.467 rad/s

7 0
3 years ago
Plz answer these two questions. I am so sick.if u ddo it would mean a lot.
faltersainse [42]
Gurlll same I hate physics
4 0
3 years ago
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