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Liula [17]
3 years ago
6

A car drives around a horizontal, circular track at constant speed. Consider the following three forces that act on the car: (1)

The upward normal force exerted on the car by the road, (2) the downward gravitational force on the car, (3) and the frictional force that is directed toward the center of the circular path.
Physics
1 answer:
DiKsa [7]3 years ago
8 0

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Three resistors of 4.0 ohms, 6.0 ohms, and 12 ohms are connected in parallel to an applied potential difference of 12 volts. (1)
lesantik [10]

Answer:

(1) 2 ohms

(2) 12 Volts Across each resistor

(3) I₁ = 3 A, I₂ = 2 A, I₃ = 1 A

Explanation:

From the question,

(1) Equilvalent Resistance (Rt) for parallel connection is

1/Rt =(1/R₁)+ (1/R₂) + (1/R₃)

Where R₁ = 4 ohms, R₂ = 6 ohms, R₃ = 12 ohms

1/Rt = 1/4 +1/6 +1/12

1/Rt = (3+2+1)/12

1/Rt = 6/12

1/Rt = 1/2

Rt = 2 ohms.

(2) Since the resistors are connected in parallel, They will have the same potential difference across them,

Hence the P.d across each resistor = 12 Volts.

(3) For R₁,

I₁ = V/R₁ = 12/4

I₁ = 3 A.

For R₂,

I₂ = V/R₂

I₂ = 12/6

I₂ = 2 A

For R₃,

I₃ = V/R₃

I₃ = 12/12

I₃ = 1 A

4 0
3 years ago
A charge Q is distributed uniformly on a non-conducting ring of radius R and mass M. The ring is dropped from rest from a height
mihalych1998 [28]

Answer:

Check below for the explanation

Explanation:

Since it is stated that the ring is dropped from a height, h, through a non uniform magnetic field, two kinds of force will act on the ring, namely:

  • A magnetic force (that is non uniform since the field is  non uniform)
  • Gravitational force

A certain amount of torque is provided by the non uniform magnetic force on the ring while the force gravity pulls it down. Due to the downward pull by the force of gravity on the ring and the torque acting on it as a result of the non uniform magnetic force, the ring begins to rotate.

5 0
3 years ago
A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline o
storchak [24]

Answer:

Explanation:

The sum of the pore along the plane is expressed according to Newton's law

Fn-Ff = ma

Fn is the moving force

Ff = nR = frictional force

m is the Mass

a is the acceleration

Substitute the given values

Fn - nR = ma

Fn - tan31°(mgcostheta) =3.9(9.8)

Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)

Fn - tan31(38.22cos31)= 38.22

Fn - 32.76tan31 = 38.22

Fn-19.68 = 38.22

Fn = 38.22+19.68.

Fn = 57.90N

Hence Fn (moving force) of the inclined block is 57.90

4 0
3 years ago
A girl pushes her little brother on his sled with a force of 300 N for 750 m.
Katarina [22]

Answer:

W = F× d

= 300×750

= 225000

E = 225000

P = 300×750/25 = 9000

P = 300× 750/10 = 22500

7 0
3 years ago
How is tidal energy obtained
yKpoI14uk [10]
Under water turbans that are placed at the above to middle of the ocean they are used to capture kinetic motion
7 0
4 years ago
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