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tresset_1 [31]
3 years ago
13

Help please I don't understand!!!

Mathematics
1 answer:
shusha [124]3 years ago
3 0
A- 2b = 2  one of the 2 "A" most be negative so they can cancer each other 
-a- b = 6   after the "A" cancel each other add the -2b with -b = -3b, then add 2 
--------------    and 6 
    -3b=8    then you have to divide 8 by -3 = -2.6       -2.6 its b... now you have to solve for b       step  1.  a -2b = 2   step 2.   a -2(-2.6)=2     step 3   a -5.3 = 2  then subtract -5.3 with 2 so that going to be 2 + 5.3 =7.3 then divide by a 
final answer (-2.5,-7.3)
sorry its kinda hard to explained here, i hope you get the point :)


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Hope this helps :)
4 0
3 years ago
one cabinet measures 3 feet by 2.5 feet by 5 feet. a second measures 4 feet by 3.5 feet by 4.5 which volume is greater explain
prisoha [69]
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3 years ago
Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
Naily [24]
The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
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Face diagonal is a hypotenuse of a right triangle which sides are a and a:
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Volume of a cube with side a is: V = a³
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V = a³ = (D/√3)³

We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
What is the answer please help no links I will report
fomenos
I found the answer. hehehehehehehehrheehrhrh

5 0
2 years ago
Combine like terms: <br> -w^3+8-2w^3-10
Lady bird [3.3K]

Answer:

Step-by-step explanation:

3w^3-2

7 0
3 years ago
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