You don't need to construct a Venn Diagram, it is just part of the instruction. Just determine whether or not the argument is va
lid or not with support.
Construct a Venn diagram to determine the validity of the given argument.
Argument:
1. All poets are loners.
2. All loners are taxi drivers.
Therefore, all poets are taxi drivers.
Choices:
- The argument is valid.
- The argument is invalid.
Please provide explanation for whether the argument is valid or not.
Construct a Venn diagram to determine the validity of the given argument.
Argument:
1. All poets are loners.
2. All loners are taxi drivers.
Therefore, all poets are taxi drivers.
Choices:
- The argument is valid.
- The argument is invalid.
Please provide explanation for whether the argument is valid or not.
1 answer:
Answer:
It is valid.
Venn Diagram is attached.
I also provided a truth table.
I also provided a couple of names this argument could be called.
Please let me know if you have any questions about this question.
Thank you kindly.
Step-by-step explanation:
If a person is a poet, then that person is a loner.
If a person is a loner, then that person is a taxi driver.
If a person is a poet, then that person is a taxi drive.
This is in the form:
p->q
q->r
Therefore, p->r.
This is an example of a hypothetical syllogism.
The first thing my mind goes to when seeing this is the transitive property which says if A is related to B and B is related to C then A is related to C.
So this syllogism also has another name and it is called the principle of transitivity of implication.
Let p=person is a poet, q=person is a loner, and r=person is a taxi driver.
I'm going to make a truth table and compare the truth values of the propositions to the conclusion.
Since we have 3 variables, we are going to need 2^3=8 rows.
p q r p->q q->r (p->q) and (q->r) conclusion=(p->r)
T T T T T T T
T T F T F F F
T F T F T F T
T F F F T F F
F F F T T T T
F F T T T T T
F T F T F F T
F T T T T T T
So we are trying to see if we ever have the preposition part true and the conclusion false.
That doesn't happen so the argument is valid.
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Answer:
<h2>See the explanation.</h2>Step-by-step explanation:
(a)
= A.
In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.
The numbers represents the corresponding sales in the month of January.
The sale is same for the 6 months.
Hence, 6A = . This matrix 6A represents the total sales over the 6 months.
(b)
If we denote the books in stock at the starting of January by B, then
B = .
Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.
If we represent the amount restocked books at the end of each month by another matrix C, then
C = .
This restocking will be done for 5 times before the end of June.
If there would be no sale, then the stock would be
B + 5C = .
Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,
B+5C-6A